Find the coordinates of the point p which is 3/4 of the way from a(3,1) to b(-2,5)
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Hey mate , here is your answer ....
Step-by-step explanation:
Let the length AB = x units
From the question , we have
AP = 3x/4
and ,
PB = x/4
Now , AP : PB
= 3x/4 : x/4
= 3:1
Let the coordinates of point P be ( x 1 , y 1 ).
Using section formula ,
x 1 = ( 3 + -2×3 ) / ( 3 + 1 ) = ( 3 - 6 ) / 4 = -3/4
y 1 = ( 1 + 3 × 5 ) / ( 3 + 1 ) = ( 1 + 15 ) / 4 = 16/ 4 = 4 4
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Hence , the required coordinates of P are
( -3/4 , 4 ) .
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