Math, asked by Anonymous, 8 months ago

find the coordinates of the point that quantized the line segment joining A(8,4) and B( - 8 ,- 6)

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Answers

Answered by Yashicaruthvik
3

Answer:

Section formula :</p><p></p><p>Any point let say (x,y) divides the line joining points (x1 ,y1 ) &amp; (x2 ,y2 ) in the ratio m:n, then co-ordinates were given by the formula</p><p></p><p>x \: = \frac{x1 \times n \: + y1 \times m}{m + n}x=m+nx1×n+y1×m</p><p></p><p>y \: = \frac{y1 \times n \: + y2 \times m}{m + n}y=m+ny1×n+y2×m</p><p></p><p>Given points A(−6,8) and B(8,−6)</p><p></p><p>(i) Point P(x,y) divides AB in the ratio 1:3</p><p></p><p>x \: = \frac{( - 6) \times 3 + 8 \times 1}{1 + 3} = \frac{ - 5}{2}x=1+3(−6)×3+8×1=2−5</p><p></p><p>y \: = \frac{8 \times 1 + ( - 6) \times 1}{1 + 3} = \frac{9}{2}y=1+38×1+(−6)×1=29</p><p></p><p>Then,</p><p></p><p>(ii) Point Q(x,y) divides AB in the ratio 2:2=1:1</p><p></p><p>x \: = \frac{( - 6) \times 1 + 8 \times 1}{1 + 1} = 1x=1+1(−6)×1+8×1=1</p><p></p><p>y \: = \frac{8 \times 1 + ( - 6) \times 1}{1 + 1} = 1y=1+18×1+(−6)×1=1</p><p></p><p>Then, Q(1,1)</p><p></p><p>(iii) Point R(x,y) divides AB in the ratio ratio 3:1</p><p></p><p>x \: = \frac{( - 6) \times 1 + 8 \times 3}{1 + 3} = \frac{9}{2}x=1+3(−6)×1+8×3=29</p><p></p><p>y \: = \frac{( 8) \times 1 + ( - 6) \times 3 }{1 + 3} = \frac{ - 5}{2}y=1+3(8)×1+(−6)×3=2−5</p><p> \\

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Answered by kanishkagupta1234
2

Answer:

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