Question

Find the coordinates of the point which
divides AB
in the ratio 3:2 from A
A.
the coordinates of A and B are (3,2)
and (-2,-5) respectively.
​

Answer 1

Answer:

0,-2

Explanation:

We know that,

Using section formula,

$x = ( \frac{m1x2 + m2x1}{m1 + m2}) \: y = (\frac{m1y2 + m2y1}{m1 + m2})$

Here,

= m1 = 3

= m2 = 2

= A(3,2)

= B(-2,-5)

$x = ( \frac{3 \times (- 2) + 2 \times 3}{3 + 2} ) \: \\ y = (\frac{3 \times ( - 5) + 2 \times 2}{3 + 2} )$

$x = (\frac{ - 6 + 6}{5} ) \: y = ( \frac{ - 15 + 4}{5} )$

$x = (\frac{0}{5} ) \: y = ( - \frac{10}{5} )$

$(x = 0) \: (y = - 2)$

Hence the coordinates of AB are 0,-2