Question

Find the coordinates of the point which divides the line joining the points (-1,7) and (4,-3) in the ratio 2:3

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Solution!!

Let P = (x, y) divide the lines A(x₁, y₁) and B(x₂, y₂) in the ratio m:n.

Here,

x₁ = -1

y₁ = 7

x₂ = 4

y₂ = -3

m = 2

n = 3

Use the section formula.

$\sf{(x,\: y)=\left(\dfrac{mx_{2}+nx_{1}}{m+n},\: \dfrac{my_{2}+ny_{1}}{m+n}\right)}$

$\sf{(x,\: y)=\left(\dfrac{2(4)+3(-1)}{2+3},\: \dfrac{2(-3)+3(7)}{2+3}\right)}$

$\sf{(x,\: y)=\left(\dfrac{8-3}{5},\: \dfrac{-6+21}{5}\right)}$

$\sf{(x,\: y)=\left(\dfrac{5}{5},\: \dfrac{15}{5}\right)}$

$\sf{(x,\: y)=\left(1,\: 3\right)}$

Hence, the coordinates of point P are (1, 3).

Additional information:-

External Section Formula ↓

$\sf{(x,\: y)=\left(\dfrac{mx_{2}-nx_{1}}{m-n},\: \dfrac{my_{2}-ny_{1}}{m-n}\right)}$