Find the coordinates of the point which divides the line segment joining the points (4, –7) and (-5, 6) internally in the ratio 7:2.
Answers
Answer:
Thank you for the points...
Given the points A(-2,3) and B (4,7). We have to find the coordinate of points which divide the line segment internally in the ratio 4:7
Point C divides the segment AB in the ratio 4:7, hence m=4, n=7
By section formula which states that when the line segment is divided internally by the point in the ration m:n then coordinates of point are
C=(\frac{(mx_2+nx_1)}{(m+n)},\frac{(my_2+ny_1)}{(m+n)})C=(
(m+n)
(mx
2
+nx
1
)
,
(m+n)
(my
2
+ny
1
)
)
Substituting the values, we get
C=(\frac{(4(4)+7(-2)}{(4+7)},\frac{(4(7)+7(3)}{(4+7)})C=(
(4+7)
(4(4)+7(−2)
,
(4+7)
(4(7)+7(3)
)
=(\frac{2}{11},\frac{49}{11})(
11
2
,
11
49
)
use the above formula
put the values
m = 7 and n = 2 as the line is divided in the ratio of 7:2
x1 = 4
x2 = -5
y1 = -7
y2 = 6
