Question

find the coordinates of the point which divides the line segment joining the point A and B in the ratio 1:3 internally. ​

Answer 1

Answer:

Let (h,k) be the point which divides the line segment joining points (1,−3) and (−3,9) in the ratio 1:3 internally.

By section formula,

(h,k)=(

3+1

1×3+1×(−3)

,

1+3

−3×3+9×1

)=(0,0)

Hence the origin divides the line segment joining points (1,−3) and (−3,9) in the ratio 1:3 internally.