Math, asked by anubhavkhanna2006, 4 months ago

Find the coordinates of the point which is equidistant from the vertices of Δ ABC, where
A(3, − 1), B(− 1, − 6) and C(4, − 1)

Answers

Answered by krantidhone30
0

Answer:

Point which is equidistant from vertices of triangle is termed as circumcentre of that triangle. For a right triangle the circumcentre is the mid point of hypotenuse.

Thus here coordinates of circumcentre must be mid point of AB

(x,y)

Answer - Option A

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