Find the coordinates of the point which
is ony- axis and which is equidistant from
points (5,-2) and (3,4).
Answers
Answered by
8
Answer:
0,-2
Step-by-step explanation:
Point on y-axis x=0
point=(0,y)
equidistant from (5,-2) and(-3,2)
distance from first point=(25+y^2+y-4y)^1/2
distance from second point=(9+y^2+4-4y)^1/2
both equals
squaring both
29+y^2+4y=13+y^2-4y
8y=-16
y=-2
point=(0,-2)
hope it helps you.....
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