Find the coordinates of the point (x,y) which divides the join of (-1, 7) and (4,3) in the ratio 2:3
Answers
Answered by
2
x= (2×4+3×-1)/(2+3)
x= (8-3)/5
=5/5
= 1
Y= (2×3+3×7)/(2+3)
=(6+21)/5
= 27/5.
(x,y) = (1, 27/5 )
x= (8-3)/5
=5/5
= 1
Y= (2×3+3×7)/(2+3)
=(6+21)/5
= 27/5.
(x,y) = (1, 27/5 )
Answered by
4
let (-1,7)=(x1,y1)
(4,3)=(x2,y2)
2:3=m:n
by formula
X=mx2+nx1÷m+n=2(4)+3(-1)÷2+3
=8-3÷5
=5÷5
=1
Y=my2+ny1÷m+n
=2(3)+3(7)÷2+3
=6+21÷5
=27÷5
it will help you
(4,3)=(x2,y2)
2:3=m:n
by formula
X=mx2+nx1÷m+n=2(4)+3(-1)÷2+3
=8-3÷5
=5÷5
=1
Y=my2+ny1÷m+n
=2(3)+3(7)÷2+3
=6+21÷5
=27÷5
it will help you
Similar questions