find the coordinates of the point y-axis which is equidistant from the point M (-5 ,-2) and N (3 ,2)
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So the answer is:
point on y-axis x=0
point=(0,y)
equidistant from (5,-2) and(-3,2)
distance from first point=(25+y^2+y-4y)^1/2
distance from second point=(9+y^2+4-4y)^1/2
both equals
squaring both
29+y^2+4y=13+y^2-4y
8y=-16
y=-2
point=(0,2)
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