Question

find the coordinates of the points lying on the y--axis,P(0 , y),when the distance between points P and A (5,4) is 13

Answer 1

Step-by-step explanation:

$distance \: formula \\ \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

$pa = \sqrt{(5 - 0) {}^{2} + (4 - y) {}^{2} } = 13 \\ = > \sqrt{25 + 16 + y {}^{2} - 8y} = 13 \\ = > \sqrt{41 + y {}^{2} - 8y} = 13 \\ = > 41 + y {}^{2} - 8y = 13 { }^{2}$

$= > y {}^{2} - 8y + 41 - 169 = 0 \\ = > y {}^{2} - 8y - 128 = 0$

$.......y = 16(or)y = 8 \\ the \: points \: lying \: on \: the \: y-axis \: is \: y = 8y \: (or)= 16$

Answer 2

heya.

here is your answer..