Question

Find the coordinates of the points of trisection (i.e., points dividing into three equal parts) of the line segment joining the points A(2, – 2) and B(– 7, 4).

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Answer 1

Step-by-step explanation:

Let P and Q are the points of trisection of AB , i.e. AP =PQ=QB

Therefore, P divides AB internally in the ratio of 1:2.

Therefore, the coordinates of P, by applying the Section formula ,are

[1(-7)+2(2)/1+2 , 1(4)+2(-2)/1+2 ]

[-7+4/3 , 4-4/3]

[-3/3 , 0/3]

[-1 , 0]

Now, Q also divides se AB internally in the ratio 2:1,

So, the coordinates of Q are,

{2(-7)+1(2)/2+1 , 2(4)+1(-2)/2+1}

{-14+2/3 , 8-2+3}

{-12/3 , 6/3}

{-4,2}

Therefore, the coordinates of the point of the transaction of line segment joining A and B are (-1,0) and (-4,2)

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Answer 2

Answer:

tq ........

Step-by-step explanation:

its.my answer