Question

Find the coordinates of the points of trisection of the line segment joining the points

A(2, −2) and B(−7, 4).​

Answer 1

Answer:

let P and Q are trisection point

let coordinate of point P are x,y

and ratio m1:m2 = 1:2

By section formula

x = m1x2 + m2x1/m1 + m2

x = 1 × -7 + 2 × 2/ 1+2

x = -7 + 4/3

x = -3/3 = -1

and y = m1y2 + m2y1/m1 + m2

y = 1×4 + 2×-2/ 3

y = 4 - 4 /3 = 0/ 3 = 0

therefore P ( -1 , 0 )

And Q coordinate x , y

ratio m1 : m2 = 2 :1

By section formula

x = m1x2 + m2x1/ m1 + m2

x = 2 ×-7 + 1 × 2/3

x = -14 + 2/3

x = -4

and y = m1y2 + m2y1/m1+m2

y = 2 ×4 + 1×-2/3

y = 8-2/3 = 6/3 = 2

Q ( -4 , 2 )

Step-by-step explanation:

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