Find the coordinates of the points of trisection of the line joining the points (-3,0) and (6,0)
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Answer:
p=[1(6)+2(-3)/1+2,1(0)+2(0)/1+2]
p=[6-6/3,0+0/3]
p=[0/3,0/3]
p=[0,0]
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By using section formula which is internally divided.As it is given as points of trisection there must be 2 points between (-3,0) and (6,0) and we know that ratios will be 1:2 for first point and 2:1 for second point.Substituting these in the formula separately then we will get the first coordinate as(0,0) and second coordinate as (3,0).
HOPE THIS HELPS,BUT TRY YOURSELF ALL THE SIMPLIFICATION.......
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