Question

find the coordinates of the points of trisection points dividing the line segment in three equal parts of the line segment joining the point (2- 2) and (-7,4)​

Answer 1

Answer:

Let P and Q are the points of the trisection of the line segment joining the points A and B

Here AP = PQ = QB   



 AP = 1

PQ = 1

QB = 1

Section formula internally = (Lx₂ + mx₁)/(L + m) , (Ly₂ + my₁)/(L + m)

P divides the line segment in the ratio 1:2

L = 1      m = 2    

  =  [(1(-7)) + 2(2)]/(1+2) , [1(4) + (2(-2)]/(1+2)

  =  (-7 + 4)/3 , (4 - 4)/3

  =  -3/3 , 0/3

  =  P (-1 , 0)

Q divides the line segment in the ratio 2:1

L = 2      m = 1    

   = [(2(-7)) + 1(2)]/(2+1) , [2(4) + 1(-2)]/(2+1)

   = (-14 + 2)/3 , (8 - 2)/3

   =  -12/3 , 6/3

   =  Q (-4 , 2)