Question

• Find the coordinates of the points on the x-axis which
are at a distance of 10 units from the point (-4, 8).​

Answer 1

Hey mate, hope it helps you.....

Answer 2

Answer:

B(-4,8 )

AB =10

AB =10

AB = 100 [(X-(-4)]² +0-8² =100

(X+4)² +(-8)² =100 X²+16+8X+64=100

X² +8x+64 +16 =100 X²+8x-20=0

x²+10x-2x-20 =0

x (x+10) -2(x+10)=0

(x+10)(x-2)=0

x=-10,x=2

This is your answer

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