Question

Find the coordinates of the points on the x-axis which are at a distance of 10 units from the point (-4,8)​

Answer 1

Step-by-step explanation:

a point on X axis = ( a, 0 )

distance from tat point to ( - 4 , 8 )= 10 units

$distance = \sqrt{(x2 - x1) ^{2} + (y2 - y1) ^{2} }$

$10 = \sqrt{(a + 4) ^{2} +( 0 - 8) ^{2} }$

$10 = \sqrt{(a + 4) ^{2} + 64}$

$squaring \: on \: both \: sides$

$100 = (a + 4) ^{2} + 64$

$(a + 4) ^{2} = 36$

$a + 4 = 6 \: or \: a+ 4 = - 6$

$a = 2 \: or \: a = - 10$

$required \: coordinates \: are \:$

(2,0) , (-10,0)