Question

find the coordinates of the points on the y axis which are at the distance of 10 units (-8,4)​

Answer 1

Step-by-step explanation:

distance =10

squaring on both sides

distance²=10²

(-8-x) + (4-0) = 100

64 + x² + 16x + 16 =100

x²+ 16x + 80 = 100

x² + 16x + 80 - 100 = 0

x² + 16x - 20 = 0

solving by quadratic formula

D= b²-2ac

here a = 1, b = 16 and c = -20

putting these values in above formula

D= (16)² + 2(1)(-20)

= 256 - 40

= 216

quadratic formula

x = -b±√d /2a

= -16±√216 /2(1)

x = -16+√216/2. or. x = -16-√216/2

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