Question

find the coordinates of the points on x-axis which r equidistant from the points (-5,8)&(6,-4)?​

Answer 1

Answer:

Step-by-step explanation:

let the point br (x,0) as the point is on x axis

distance from (-5,8) to (x,0) is equal to distance from (6,-4) to (x,0)

(x+5)^2+(8^2)=(x-6)^2+4^2

x^2+25+10x+64=x^2+36-12x+16

22x+48=11

22x=-37

x=-37/22