Question

Find the coordinates of the points which divides the join of (-1, 7) and (4, -3) in the ratio 2:3​

Answer 1

Using section formula the coordinates will be-

$(\frac{mx2+nx1}{m+n} , \frac{my2+ny1}{m+n})$

m=2

n=3

x2= 4

x1= -1

y2= -3

y1= 7

Substitute the values, you will get the answer

: )

Answer 2

Step-by-step explanation:

Using section formula :

$\sf \:x, \: y = \frac{{mx}_{2} + {nx}_{1}}{m + n} \frac{{my}_{2} + {ny}_{1}}{m + n}$

Where,

m = 2

n = 3

$\sf {x}_{1} = -1$

$\sf {x}_{2} = 4$

$\sf {y}_{1} = 7$

$\sf {y}_{2} = (-3)$

Substitution of the values :

$\longmapsto \sf \:x, \: y = \frac{{mx}_{2} + {nx}_{1}}{m + n}, \frac{{my}_{2} + {ny}_{1}}{m + n} \\ \longmapsto \sf \:x, \: y = \frac{8 + ( - 3)}{5} , \frac{ - 6 + 21}{5} \\ \sf \: \longmapsto x, \: y = \frac{5}{5} , \frac{15}{5} \\ \sf \: \longmapsto x, \: y =( 1, 3 )\: ans.$