Question

Find the coordinates of the qon the x axiswhich lies on perpendicular bisector of line segment joining point A(-5,-2) B(4,-2).name the type of triangle formed by points q,a,b

Answer 1

Given:-
A(-5,-2) and B(4,-2)
It show that the line segment AB is parallel to x-axes, so the perpendicular bisector will be parallel to y-axes and we just need to find the value of x coordinate(Q) as y = 0.
∴ Q = $( x_{2} + x_{1})/2 = (4-5)/2 = -1/2 = -0.5$

ΔQAB is an isosceles triangle, because the point Q lies in perpendicular bisector of line segment AB divides into two equal halves.   

Answer 2

Given:-
A(-5,-2) and B(4,-2)
It show that the line segment AB is parallel to x-axes, so the perpendicular bisector will be parallel to y-axes and we just need to find the value of x coordinate(Q) as y = 0.
∴ Q = ( x_{2} + x_{1})/2 = (4-5)/2 = -1/2 = -0.5(x2​+x1​)/2=(4−5)/2=−1/2=−0.5

ΔQAB is an isosceles triangle, because the point Q lies in perpendicular bisector of line segment AB divides into two equal halves