Question

find the coordinates of the vertices and foci of the equation x^2÷16-y^2÷9=1

plzzz answer qns.....and help me dear frnds....​

Answer 1

Answer:

vertices (+4,0) and (-4,0)

foci(+5,0) and (-5,0)

Step-by-step explanation:

since this is first hyperbola

a=4. b=3

vertices(a,0) and (-a,0)

vertices(4,0) and (-4,0)

foci(5,0) and (-5,0)