Find the coordinates the centroid of a circle whose vertices are (0,6) , (8,12) & (8,0)
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Heya,
According to the question,
Vertices of a circle are;
(0, 6) => (x1, y1)
(8, 12) => (x2, y2)
(8, 0) => (x3, y3)
Formula for finding centroid is =>
(x, y) => [(x1 + x2 + x3)/3 , (y1 + y2 + y3)/3]
(x, y) = [(0 + 8 + 8)/3 , (6 + 12 + 0)/3]
(x, y) = (16/3 , 18/3)
(x, y) = (16/3 , 6)
x = 16/3. and. y = 6
Coordinates of centeroid = (16/3, 6)
Hope this helps....:)
According to the question,
Vertices of a circle are;
(0, 6) => (x1, y1)
(8, 12) => (x2, y2)
(8, 0) => (x3, y3)
Formula for finding centroid is =>
(x, y) => [(x1 + x2 + x3)/3 , (y1 + y2 + y3)/3]
(x, y) = [(0 + 8 + 8)/3 , (6 + 12 + 0)/3]
(x, y) = (16/3 , 18/3)
(x, y) = (16/3 , 6)
x = 16/3. and. y = 6
Coordinates of centeroid = (16/3, 6)
Hope this helps....:)
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