find the coordinatesof the third vertex of a triangle whose two vertices arecentroid are (0,0) (5,6) and (0,3) respectively
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x=x1+x2+x3 divide by 3
=0+5+0/3
x=5/3
y= y1+y2+y3 divide by 3
0+6+3/3
9/3
3
y=3
there for third vertex are(5/3,3)
=0+5+0/3
x=5/3
y= y1+y2+y3 divide by 3
0+6+3/3
9/3
3
y=3
there for third vertex are(5/3,3)
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