Question

find the cordinates of the point which divides the join of a(-6, 10) and B(3, -8) in the ratio2:7​

Answer 1

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

(a) Let the point be P(x,y)

(x,y)=(

2+3

2×−7+3×8

,

2+3

2×4+3×9

)

X=2,Y==7

So the point is (2,7)

(b) Let the required point be P(x,y)

Then,

(x,y)=(

1+2

1×4+2×1

,

1+2

1×7+2×−2

)

x=2,y=1

therefore, required point (2,1)

Answer 2

Answer:

hope it helps you

btw can I be you friend