Question

find the cosine and sine of the angle between A =(3i cap +j cap+k cap)and B=(-2i cap +j cap+ k cap)​

Answer 1

Answer:

Ans. Is 60°.

Solution: Do dot product.

let A= I+j nd B= 2j+2k

Now, A.B =|A||B|Cos(Theta)

        (I+j).(2j+2k) = 4×Cos(Theta)

         2=4× Cos(Theta)

  So Cos(Theta)= 1/2

    So Theta=Angle = 60°.............mark as brainliest