Question

Find the cosine of angle between the vectors:
p = 7i - 2j and q = -4i + 3j

Answer 1

Step-by-step explanation:

use dot product

(vector p) . (vector q)=( magnitude of p)(magnitude of q) ×cosine(x)

(-28-6)=(root 53)(root 25)cosine(x)

-34=5root (53)× cos(x)

now u can calculate

cosx by dividing it..

Answer 2

p.q = pq cos theta

So by dot product

p.q = (7i - 2j). ( -4i+ 3j)

Always, i.i, j.j, k.k = 1

i.j, j.k, k.i = 0

p.q = -28-6

p.q = -34