find the cosine of the angle between the lines whose direction cosines are (1/√3,1/√3,1/√3) and (1/√2,1/√2,0)
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cos theta= l1l2+m1m2+n1n2
=1/√3×1/√2 +1/√3+1/√2 +0
=2/√6
by rationalisation of denominator
=√6/3
√3×√2/√3×√3
=√2/3
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