Question

Find the cost of
a) 8 books when 6 books cost $48, given that the price of each book is the same.
b) 10kg of tea when 3 kg of tea cost $18.
c) a kg of sugar when b kg of sugar cost c dollars.

Answer 1

Answer:

GIVEN -

• 6 books = $ 48
• 3kg tea= $ 18
• b kg sugar= $ C

TO FIND -

• cost of 8 books
• 10kg tea
• A kg sugar

SOLUTION -

i) 6 books = 48 $

8 books = ?

8 × 48/6

4× 48/3

4 × 16

64$

ii) 3 kg tea= $ 18

10 kg = ?

10 × 18/3

10 × 6

60$

iii) b kg = C $

a kg = ?

a× C/B

ac/b $

Answer 2

Answer:

a) 6 books =48 dollars

1 book = 8 dollars

8 books = 8*8

64 dollars

b) 3kg tea = 18 dollars

1kg = 6 dollars

10kg = 60 dollars

c) x is the cost we need to find

if b---->c

and a,---->x

crossmultiplying,bx=ac

x=ac/b

This the cost of a books