find the cost of a trapezoidal field whose parallel sides are 10m and 25m the perpendicular distance between them is 15cm and the rate of watering is rs 4 per square meter
Answers
Answered by
7
area of trapezium =
1/2 (10+25)×15 cm²
= 262.5 cm²
total cost of watering = 262.5 ×4
= 1050
1/2 (10+25)×15 cm²
= 262.5 cm²
total cost of watering = 262.5 ×4
= 1050
Answered by
4
area of trapezoidal =1/2 ×base (sum of pallel side)
area = 1/2×15(10+25)
area =1/2×15 ×35
area= 1/2×525
area=262.5
cost of watering÷
4×262.5=RS 1050.0 *ANS*
area = 1/2×15(10+25)
area =1/2×15 ×35
area= 1/2×525
area=262.5
cost of watering÷
4×262.5=RS 1050.0 *ANS*
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