Question

Find the cost of covering a playground at ₹3 per sq m if it is 30m long and 15m wide. Also find the cost of fencing it at the rate of ₹20 per metre.

Answer 1

AnswEr :

$\bold{Given} \begin{cases}\sf{Length (l)=30 \:m} \\ \sf{Breadth (b)=15 \:m}\end{cases}$

⋆ Refrence of Image is in the Diagram :

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.7,3){\large{A}}\put(7.3,2){\mathsf{\large{15 m}}}\put(7.7,1){\large{B}}\put(9.2,0.7){\matsf{\large{30 m}}}\put(11.1,1){\large{C}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(11.1,3){\large{D}}\end{picture}$

• Let's Head to the Question Now :

$\longrightarrow \tt Cost \:of \: Covering = Area \times Rate \\ \\\longrightarrow \tt Cost \:of \: Covering = (Length \times Breadth) \times Rs. 3 \:@ {m}^{2} \\ \\\longrightarrow \tt Cost \:of \: Covering =(30m \times 15m) \times3 \\ \\\longrightarrow \tt Cost \:of \: Covering =45 {m}^{2} \times Rs.3 \\ \\\longrightarrow \tt Cost \:of \: Covering =450 {m}^{2} \times Rs.3 \\ \\\longrightarrow \boxed{\orange{\tt Cost \:of \: Covering =Rs. \:1350}}$

⠀

∴ Cost of Covering of Ground is Rs. 1350

$\rule{300}{2}$

• Second Part of the Question Now :

$\longrightarrow \tt Cost \:of \:Fencing = Perimeter \times Rate \\ \\\longrightarrow \tt Cost \:of \:Fencing = 2(Length + Breadth) \times Rs. 20 \:@m \\ \\\longrightarrow \tt Cost \:of \:Fencing = 2(30m + 15m) \times Rs. 20 \\ \\\longrightarrow \tt Cost \:of \:Fencing = 2 \times45m \times Rs. 20 \\ \\\longrightarrow \tt Cost \:of \:Fencing = 90m \times Rs. 20 \\ \\\longrightarrow \boxed{ \blue{\tt Cost \:of \:Fencing = Rs. \:1800}}$

⠀

∴ Cost of Fencing of Ground is Rs. 1800.

#answerwithquality #BAL

Answer 2

Answer:

$\huge\underline\mathfrak{Answer\::}$

$\textbf{\underline{Given\::}}$

● Length of playground= 30 m

● Width of playground = 15 m

$\textbf{\underline{To\:find\::}}$

● Cost of covering at Rs.3 sq.m

● Cost of fencing at Rs.20 per m

$\textbf{\underline{Solution\::}}$

Area =Length × Width

=> Area = (30 × 15) sq.m

=> Area = 450 sq.m

Cost of covering =Area × Rate

=> Cost of covering =Rs.(450 × 3)

=> Cost of covering = Rs. 1350 ★

$\rule{300}{2}$

Perimeter = 2 (length + width)

=> Perimeter = 2 (30 + 15) m

=> Perimeter =( 2 × 45 )m

=> Perimeter = 90 m

Cost of fencing = Perimeter × Rate

=> Cost of fencing = Rs.(90 × 20)

=> Cost of fencing = Rs. 1800 ★

$\rule{300}{1}$

Cost of covering the playground => Rs.1350

$\rule{300}{2}$

Cost of fencing the playground => Rs.1800

Hope it helps you ♥ ♥ ♥