Question

find the cost of covering the floor of a room 9 by 6 with tiles each tile measuring 25 CM by 30 cm @ rupees 200 Per tile​

Answer 1

ANSWER :

=₹ 144000

STEP - BY - EXPLANATION :

Dimensions of floor = length = 900 cm and breadth = 600 cm

Dimensions of floor = length = 900 cm and breadth = 600 cm area of floor = lb = 900 cm× 600 cm

= 540000 cm²

Dimensions of tile = length = 25cm and

breadth =30cm

area of floor = lb = 30cm×25cm

750 cm²

Nomber if tiles required ti cover = area of floor ÷ area of tile = 540000/750

=720

cost of tile = ₹200

Total cost of tiles = 720 ×200

=₹ 144000

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