find the cost of covering the floor of a room 9 m by 6 m with tiles each tile measuring 25 cm by 30 cm at Wide?
Answers
Answered by
7
Cost of floor= (9×100cm×6×100cm/25×30cm^2)× cost of 1 tile
=30×6×4×cost of tile
=720×cost of tile
Similar questions
Math,
4 months ago
Biology,
4 months ago
Political Science,
9 months ago
Science,
9 months ago
Math,
11 months ago