find the cost of covering the floor of a room 9 metre by 6 metre with tiles each measuring 25 CM by 30 cm at wide
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Answer:
The cost of covering the floor = 60r
Step-by-step explanation:
I can find the number of tiles only. It's because you don't mention the rate. Let's the rate of each tile r.
Area of the floor = lb
= 9m *5m
=45 sq.m
1 sq.m = 1000sq.cm
Area of the floor = 450000sq.cm
Area of the tile =lb
=25cm*30cm
=750sq.cm
Number of tiles = (Area of the floor)/(Area of tile)
= 450000/750
= 60
The cost of covering the floor = No. of .tiles× rate
= 60r
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