Question

FIND THE COST OF COVERING THE FLOOR OF A ROOM 9M BY 6M WITH, TILES MEASURING 25CM BY 30CM, AT THE RATE OF ₹200 PER TILE.​

Answer 1

Answer:

Rs.1,44,000

Step-by-step explanation:

Length of floor= 9m

Breadth of floor=6m

Area of floor=l×b = 9×6=

$= 54m^{2}$

Length of tile= 25cm=.25m

Breadth of tile=30cm=.30m

Area of tile= .25×.30

$= 0.075m^{2}$

Number of tiles used= Area of the floor÷Area of tile

= 54÷.075=720

Cost of each tile = Rs.200

Cost of tiles= 720×200=Rs. 1,44,000

Hope this will help you.

Answer 2

Answer:

Answer:

Rs.1,44,000

Step-by-step explanation:

Length of floor= 9m

Breadth of floor=6m

Area of floor=l×b = 9×6=

Length of tile= 25cm=.25m

Breadth of tile=30cm=.30m

Area of tile= .25×.30

Number of tiles used= Area of the floor÷Area of tile

= 54÷.075=720

Cost of each tile = Rs.200

Cost of tiles= 720×200=Rs. 1,44,000