find the cost of covering the floor of a room 9m by 6m with tiles, each tile measuring 25cm by 30cm, at the rate of $200 per tile.
Answers
Answered by
7
Answer:
area of the floor =9*6 =54
area of tiles=0.25*0.3=0.75
total tiles required=54/0.75=720
cost=720*200=144000$
anveshajain23:
very nice answer and thank u
Similar questions