find the cost of f fencing a regular hexagon of side of 25 m the cost of fancing 1m in Rs 24
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Step-by-step explanation:
Correct option is
B
Rs 73,800
Given :
Total cost of fencing =Rs. 10080
Cost of fencing per meter =20
So perimeter =
20
10080
=504 m
So length of square =
4
504
=126 m
width of pavement =3 m
Length of inner square =126−3=120 m
So, area of pavement =Area of Outer square − Area of inner square
=126×126−120×120
Area of pavement=1476 m
2
Cost of pavement =1476×50
∴ Cost of pavement=Rs. 73800
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