Question

Find the cost of fencing a rectangular field 75m long and 32 m wide, if the cost of
fencing is ₹ 35.50 per metre.

Answer 1

Step-by-step explanation:

I hope it helps!!

Here is your Answer ➡

Length of the rectangle field =34 m

Breadth of the rectangle field =18 m

Perimeter =2(l+b)

=2(34+18)

=2×52

=104 m

Rate of fencing = Rupees 22.50 per m

Total cost = Rupees 22.5×104

= Rupees 2340

Answer 2

Step-by-step explanation:

Rupees 2340

Rupees 2340Length of the rectangle field =34 m

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 m

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)=2×52

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)=2×52=104 m

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)=2×52=104 mRate of fencing = Rupees 22.50 per m

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)=2×52=104 mRate of fencing = Rupees 22.50 per mTotal cost = Rupees 22.5×104

Rupees 2340Length of the rectangle field =34 mBreadth of the rectangle field =18 mPerimeter =2(l+b)=2(34+18)=2×52=104 mRate of fencing = Rupees 22.50 per mTotal cost = Rupees 22.5×104= Rupees 2340

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