Question

find the cost of fencing a rectangular park 30m long and 20m wide at the rate of rs4 per m

Answer 1

30+20*2=100m

100m * 4rs = Rs 400.

Therefore, cost of fencing is Rs 400.

Answer 2

Given:

• Length of the park = 30 m

• Breadth of the park = 20 m

• Cost of fencing per m = Rs 4

To calculate:

• Cost of fencing the whole rectangular park.

Calculation:

In order to calculate cost of fencing the whole rectangular park, we have to calculate the perimeter of the park first.

We know that,

$\boxed {\sf{ {Perimeter}_{(rectangle)} =2( length + breadth ) }}$

$\sf { \longrightarrow {Perimeter}_{(rectangle)} =2 (30 + 20) m}$

$\sf { \longrightarrow {Perimeter}_{(rectangle)} = 2 \times 50 \: m}$

$\sf { \longrightarrow {Perimeter}_{(rectangle)} = 100 \: m}$

Now, as per the provided question ,we know that cost of fencing per m is Rs 4. Therefore,

$\sf { \longrightarrow {Cost \: of \: fencing}_{(Whole \: park)} = Rs \:( 100 \times 4 ) }$

$\sf \red { \longrightarrow {Cost \: of \: fencing}_{(Whole \: park)} = Rs \: 400 }$

Therefore, cost of fencing the whole rectangular park is Rs 400.

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Extra Information:

Perimeter:

• Perimeter of square : 4 × side
• Perimeter of rectangle : 2 ( l + b )
• Perimeter of parallelogram : 2 ( l + b )
• Perimeter of rhombus : 4 × side
• Perimeter of trapezium : Sum of sides
• Perimeter of triangle : Sum of sides
• Perimeter of circle (circumference) : 2πr

Area:

• Area of square : (Side)²
• Area of rectangle : l × b
• Area of parallelogram : Base × height
• Area of rhombus : ½ × diagonal₁ × diagonal₂
• Area of trapezium : ½ × (sum of parallel sides) × h
• Area of triangle : ½bh
• Area of circle : πr²