Question

Find the cost of fencing a rectangular park of side 110 m and breadth 22 m at the rate of ₹5 per meter.

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Answer 1

Question :-

• Find the cost of fencing a rectangular park of side 110 m and breadth 22 m at the rate of ₹5 per meter

Given :-

• Length of Rectangular Park = 110m
• Breadth of Rectangular Park = 22m
• Cost of 1 m fencing wire = ₹ 15

To Find :-

• The cost of fencing the rectangular park with the given dimensions.

Solution :-

$\qquad \quad {:} \longrightarrow \sf \boxed{\bf{Perimeter\:of \: Rectangle \: = \: 2 \: \times \: (Length \: + \: Breadth) }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Perimeter \: = \: 2 \: \times \: (110 \: + \: 22) }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Perimeter \: = \: 2 \: \times \: 132 }}$

$\qquad \quad {:} \longrightarrow \sf {\bf{Perimeter \:of \: Rectangular \: Park = \: 264m}}$

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$\qquad \quad {:} \longrightarrow \sf \boxed{\tt{Cost\:of \: Fencing \: the \: park \: = \: 15 \: \times \: Perimeter }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Cost \: = \: 15\: \times \: 264}}$

$\qquad \quad {:} \longrightarrow \sf {\bf{Cost\:of \: Fencing \: the \: park \: = \: Rs, 3960 }}$

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$\begin{gathered}\begin{gathered} \therefore\: \sf{ Cost\:of \: Fencing \: the \: park \: = \underline {\underline{Rs, \: 3960}}}\\\end{gathered}\end{gathered}$

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More For Knowledge :-

• Perimeter of rectangle = 2(l+b)
• Perimeter of square = 4 × side
• Area of rectangle = l × b
• Area of Square = side x side sq. units
• Area of triangle = 1/2 base x height sq. units
• Area of parallelogram = base x height sq. units
• Area of circle = πr² sq. units

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Answer 2

Step-by-step explanation:

${\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{Required \: answer}}}}}}}}}}}}}}}}}}$

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$\huge\fcolorbox{black}{lime}{Question}$

Find the cost of fencing a rectangular park of side 110 m and breadth 22 m at the rate of ₹5 per meter.

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$\huge \bf{ \boxed{ \boxed{ \red{ \bigstar{ \underline{ \sf{ \blue{ \mathfrak{answer}}}}}}}}}$

Fencing is done at the perimeter so, perimeter of rectangular park

= 2( l+ b ) = 2 (110 + 22)

⇒ 2 ( l + b ) = 132

∴ ⇒ 264

Rate of fencing per meter = Rs. 5 per metre.

∴ Rate of fencing 264 = RS.5 × 264

$\huge{\underline{\blue{\mathrm{1,320}}}}$