find the cost of fencing a rectangular piece of land measuring 0.7 km by 0.5 km at the rate of 50 rupees per metre each side is to be fenced with four rows of wires
Answers
Sides of rectangular field = 0.7 km and 0.5 km
Perimeter of rectangle = 2(l + b)
Perimeter of rectangle = 2(l + b)
= 2( 0.7 + 0.5)
= 2 × 1.2
= 2.4 km
Cost of fencing per metre = Rs 50
Each side is to be fenced with four rows of wires.
Length of the wire to be fenced = 4 × Perimeter
= 4 × 2.4
= 9.6 km
Cost of fencing = 50 × 9.6
= Rs 480
Answer:
₹4,80,000
Step-by-step explanation:
Length of the rectangular piece of land = 0.7 Km = 700 metres
Breadth of the rectangular piece of land = 0.5 Km - 500 metres
Length of wire required to fence the piece of land = Perimeter x 4
= [(Length+Breadth)x2]x4
=[(700m+500m)x2]x4
=[1200mx2]x4
=2400mx4
=9600m
Cost of fencing the rectangular piece of land = ₹50 x 9600m
= ₹4,80,000