Question

Find the cost of fencing a square park of side 110 m and breadth 22 m at the rate of rupees 15 per meter

Answer 1

Correct Question:

Find the cost of fencing a rectangular park of side 110 m and breadth 22 m at the rate of ₹5 per meter

Solution :

Cost of fencing is ₹ 3,960 .

Step by step Explanatìon:

We have ,

Dimension of square:

• Length , l = 110 m
• Breadth , b = 22 m

We know that

$\sf\purple{Perimeter\:of\:rectangle,P=2(l+b)}$

Put the given values

$\sf\implies\:P=2(110+22)$

$\sf\implies\:P=2(132)$

$\sf\implies\:P=264m$

Cost of 1 m fencing wire = ₹ 15

Therefore , Cost of 264 m fencing wire

= ₹15×264

= ₹ 3,960

Therefore , the cost of fencing is ₹ 3,960

__________________

Some Important Formula's

1. Perimeter of rectangle = 2(l+b)
2. Perimeter of square = 4 × side
3. Area of rectangle = l × b
4. Area of square = side × side

Answer 2

CORRECT QUESTION:

Find the cost of fencing a ʀᴇᴄᴛᴀɴɢᴜʟᴀʀ park of side 110m and breadth 22m at the rate of ripped 15 per metre

GIVEN:

• side of the park : 110m
• breadth of the park : 22m

TO FIND:

cost of fencing the park at the rate of 15 per metre

SOLUTION:

Let "l" and "b" be the length and breadth of the rectangular park

We Know That:

${ \boxed{ \sf{ \red{perimeter \: of \: rectangle \: = 2(l + b)}}}}$

So,

$\sf{perimeter \:of \:the\: park\: = 2(l + b)}$

$\sf{perimeter \:of\: the \:park \:= 2(110 + 22)m}$

$\sf{perimeter\: of \:the \:park = 2 ×132m}$

$\sf{perimeter \:of \:the \:park\: = 264m}$

Now,

$\sf{cost \:of \:fencing \:per \:metre\: = ₹15 }$

So,

$\sf{cost\: of \:fencing \:264 metres\: = 264 × 15}$

$⟹$ ₹ $\sf\red{3,960}$

Hence,

⊱ cost of fencing the rectangular field is 3,960 rupees