Question

find the cost of fencing the quadrilateral shape land at the rate of rupees 300 per metre ​

Answer 1

Answer:

a = 120m , b =80m ,c =50m

s = (120+80+50)/2

s = 250/2 = 125

area of triangle = under root s(s-a)(s-b)(s-c)

= under root 125(125-120)(125-80)(125-50)

= under root 125*5*45*75

= under root 25*5*5*9*5*3*25

= 25*3*5 under root 15

Area of the park = 375 under root 15 m2

now perimeter = 250m

Length of barbed wire required = 250-3 = 247m

Cost of fencing 1 m = Rs 20

Cost of fencing 247 m = Rs 20*274

= Rs 4940 Ans