Question

find the cost of flooring a 15m long and 10 m wide room with tiles of area 1.5m2 at the rate of 18per tile




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Answer 1

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Length of room = 15m

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• Width of room = 10 m

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• Cost of flooring it with tiles of 1.5 m² area at the rate of 18 per tile

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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$\underline{\bold{\texttt{Area of rectangle :}}}$

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➠ Length × Breadth -------- (1)

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$\underline{\bold{\texttt{Area of floor :}}}$

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• Length = 15 m

• Breadth = 10 m

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Putting these values in (1)

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➠ Length × Breadth

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➜ 15 × 10

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➨ 150 sq. m

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$\underline{\bold{\texttt{Number of tiles required :}}}$

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➠ $\sf \dfrac { Area \ of \ floor } { Are \ of \ tile }$

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➜ $\sf \dfrac { 150 } { 1.5 }$

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➨ 100

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• Hence number of tiles required to cover the floor is 100

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$\underline{\bold{\texttt{Cost of flooring :}}}$

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➠ Number of tiles × Cost of 1 tile

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➜ 100 × 18

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➨ Rs 1800

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Hence the cost of flooring the room is Rs 1800

Answer 2

Given :-

Length of the floor = 15 m

Breadth of the floor = 10 m

Area of the tile = 1.5 m²

Rate of flooring per tile = Rs. 18

To Find :-

The cost of flooring it with tiles of 1.5 m² area at the rate of 18 per tile.

Solution :-

We know that,

• l = Length
• b = Breadth
• a = Area

By the formula,

$\underline{\boxed{\sf Area \ of \ the \ rectangle=Length \times Breadth}}$

Given that,

Length (l) = 15 m

Breadth (b) = 10 m

Substituting their values,

a = 15 × 10

a = 150 m²

Therefore, the area of the floor is 150 m².

Finding number of tiles,

Given that

Area of the tile = 1.5 m²

Area of the floor = 150 m²

According to the question,

Number of tiles = Area of floor/ Area of each tile

Substituting their values,

Tiles = 150/1.5

Tiles = 100

Therefore, 100 tiles are required.

Cost of flooring = Number of tiles × Cost of 1 tile

Substituting them,

Cost =  100 × 18

Cost = Rs. 1800

Therefore, the cost of flooring is Rs. 1800.