find the cost of flooring a room 7.5m by 6m with square tiles of side 30cm at the rate of ₹6per tile
Answers
Answered by
166
total area of the floor of the room is
7.5 x 6 = 45m²
surface area of 1 tile is
0.3 x 0.3 = 0.09m²
so total number of tiles required for flooring are
45/0.09= 500
total cost of the flooring will be
6 x 500 = ₹3000
answered :-)
7.5 x 6 = 45m²
surface area of 1 tile is
0.3 x 0.3 = 0.09m²
so total number of tiles required for flooring are
45/0.09= 500
total cost of the flooring will be
6 x 500 = ₹3000
answered :-)
Answered by
9
The cost will be, ₹300
Given : A room 7.5m by 6m with square tiles of side 30cm at the rate of ₹6 per tile.
To find : The total cost for flooring.
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the total cost)
The dimensions of the floor :
= 7.5m by 6m
= (7.5 × 100)cm by (6×100)cm
= 750cm by 600cm
(As, 1m = 100cm)
The area of the floor :
= (750 × 600) cm²
= 450000 cm²
Area of one square tile :
= (side)²
= (30)²
= 900 cm²
Numbers of tiles needed :
= (450000 ÷ 900)
= 500
Cost for 1 tile = ₹6
Cost for 500 tiles = 6 × 500 = ₹300
(This will be considered as the final result.)
Hence, the total cost ₹300
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