Find the cost of laying grass in a triangular field of side 50m ,65m,65m at the rate of rs.7mper square
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Answered by
10
Hello here is your answer by Sujeet yaduvanshi
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Question:-Find the cost of laying grass in a triangular field of side 50m ,65m,65m at the rate of rs.7mper square
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Solution:-
GIVEN:-Sides if Triangular Field 50m ,65m,65m
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Also Given:- The cost of laying grass at the rate of field=7m²
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Method of Solution:-
We know that Semi perimeter of triangle=a+b+c/2
then,
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Semi perimeter=(a+b+c)/2
=180/2=90 m.
Area:\sqrt{s(s-a)(s-b)(s-c)}s(s−a)(s−b)(s−c)
⇒\sqrt{90(90-65)(90-65)(90-50)}90(90−65)(90−65)(90−50)
⇒\sqrt{90*25*25*40}90∗25∗25∗40
=\sqrt{5 ^{6}*2 ^{4} *3^{2} }56∗24∗32
=)125×4×3
=)1500
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Now.
According to the question:-
Cost of lying grass=1500×7
=10500
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Answer:- 10500
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Thanks!!!!!
@Sujeet
________________________________
Question:-Find the cost of laying grass in a triangular field of side 50m ,65m,65m at the rate of rs.7mper square
__________________________________
Solution:-
GIVEN:-Sides if Triangular Field 50m ,65m,65m
______________________________
Also Given:- The cost of laying grass at the rate of field=7m²
_________________________________
Method of Solution:-
We know that Semi perimeter of triangle=a+b+c/2
then,
_________________________________
Semi perimeter=(a+b+c)/2
=180/2=90 m.
Area:\sqrt{s(s-a)(s-b)(s-c)}s(s−a)(s−b)(s−c)
⇒\sqrt{90(90-65)(90-65)(90-50)}90(90−65)(90−65)(90−50)
⇒\sqrt{90*25*25*40}90∗25∗25∗40
=\sqrt{5 ^{6}*2 ^{4} *3^{2} }56∗24∗32
=)125×4×3
=)1500
_________________________________
Now.
According to the question:-
Cost of lying grass=1500×7
=10500
_________________________________
Answer:- 10500
_________________________________________________
Thanks!!!!!
@Sujeet
Answered by
22
We will use Heron's Formula here,
Cost = 1500 × 7 = 10500 rupees
Noah11:
सप्रेम धन्यवाद @sujeetkumarray
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