find the cost of laying grass in a triangular field of sides 50,65 and 65 metre at the rate of rupees 7 per metre square
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Answered by
5
Answer:
Sides of the triangle are a=50m,b=65m,c=65m
Area of triangle, by Heron's formula =s(s−a)(s−b)(s−c)
where,
s=2a+b+c
s=250+65+65
s=90
Area of triangle = 90(40)(25)(25)
Area of triangle = 1500m2
Cost of laying grass = Area ×7
Cost of laying grass =1500×7
Cost of laying grass = Rs 10500
Answered by
3
Answer:
putting heron's formula of isosceles triangle b/4(4a^2-b^2)^1/2 =50/4(4×65^2-50^2)^1/2 =1500m^2 ;cost per meter ^2=7 rupees;so 1500×7=10500 rupees
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