Math, asked by rajivtgss, 2 months ago

Find the cost of leveling a field of dimensions 12 x 10m at the rate of Rs 2.5/m.

Answers

Answered by shubhampatra9315
1

Answer:

300 rupees

Step-by-step explanation:

By multiplying 10× 12 then multiply 2.5

Answered by shloksolanki
1

Answer:

RS 10500

Step-by-step explanation:

Answer

Dimensions of wall:

Length = 14 m

Breadth = 10 m

Height = 6.5 m

Dimensions of windows

Length = 1.5 m

Breadth = 1 m

And,Length of doors = 2.5 m

Breadth of doors = 1.2 m

Cost = RS 35 per m

2

Now,

Area of four walls = 2(Length of walls × Height of walls) +2(Breadth of walls × Height of walls)

=2(14×6.5)+2(10×6.5)

=182+130

=312

⇒ Area of four walls is 312m

2

Area of two doors = 2(Length of doors × Breadth of doors)

=2(2.5×1.2)

=6

⇒ Area of two doors is 6m

2

Area of four windows = 4(Length of windows × Breadth of windows)

=4(1.5×1)

=6

⇒ Area of four windows is 6m

2

Therefore,

Area to be painted = Area of 4 walls − (Area of 2 doors + Area of 4 windows)

=312(6+6)

=300

⇒ Area to be painted is 300m

2

Cost of painting =300m

2

× Rs 35 per m

2

=Rs10500

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