Question

find the cost of leveling the ground which is in the form of a traingle. having a length of side at 75m, 65m, 70m, at the rate of 5 m per square

Answer 1

Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝________________________________________________________________________________________________________________________________________________


Question:-)find the cost of leveling the ground which is in the form of a traingle. having a length of side at 75m, 65m, 70m, at the rate of 5 m per square.


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Solution:-) Given that...


Length of Sides 75,65and 70


Solving the problem by Her on formula...

S=75+65+70/2
S=210/2


S=105


Then..


Here..
a=75

b=65

C=70


So..

Using Formula...

A=√105(105-75)(105-65)(105-70)

A=√105(30)(40)(35)

A=√4410000
A=2100



Also ....

GIVEN That


Cost of leveling the Ground=2100×5

=10500



hope this helps you.

cheers!! 

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Answer 2

$\bf{\underline{\underline{Answer:}}}$

•°• ₹ 10500

$\bold{\underline {Given:}}$

• Side are 75m, 65m and 70m

• Cost = ₹ 5 per m²

$\bold{\underline {To\:find :}}$

• The cost of leveling the ground =?

$\bf{\underline{\underline{Step\: by\: step \:explanation:}}}$

Let, a = 75m, b = 65m and c = 70 m

First we have to find its semi - perimeter=

${\bigstar{\boxed{\bf Semi-Perimeter = {S = {\dfrac{a+b+c}{2}}}}}}$

${S = \dfrac{75+65+70}{2}}$

${S = \dfrac{210}{2}}$

S = 105

Now, area of triangle =

$\bigstar{\boxed{\bf Area \:of \triangle = {\sqrt{s(s-a) (s-b) (s-c)}}}}$

${Area \:of \triangle = {\sqrt {105(105-75) (105-65) (105-70)}}}$

$= {\sqrt{105 \times30\times40\times35 }}$

$= {\sqrt{105 \times15\times2\times20\times2\times35 }}$

$= 2 {\sqrt{105 \times15\times20\times35 }}$

$=2 {\sqrt{1102500}}$

$=2 {\sqrt{(1050) ^2}}$

$={2 \times 1050 }$

$= {\bf{2100\:m}}$

Cost of levelling the ground per m² = 5m²

⟹ 2100m² = 5 m

=2100×5

= ₹ 10500 Answer