Math, asked by Anonymous, 11 months ago

find the cost of levelling of plot 55 metre long and 30 metre wide at the rate of rupees 4.50 per square metre​

Answers

Answered by sahildhande987
723

To find the cost of levelling

We will need to find the area of the plot.

Given:

Length=55m

Breadth=30m

\large{\boxed{\underline{\tt{Formula}}}}

Area of Rectangle = Length \times Breadth

Solution:

Area of Rectangle = 55 x 30

\implies1650

Now, The Cost for levelling the Area

\implies Area of rectangle \times Cost

\implies 1650 \times 4.5

\implies \large{\boxed{\boxed{7425}}}


Anonymous: Good
BrainlyConqueror0901: keep it up : )
StarrySoul: Great Work!✿
Answered by BrainlyConqueror0901
180

{\bold{\underline{\underline{Answer:}}}}

{\bold{\therefore Cost\:of\:levelling\:field=7425\:rupees}}

{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

• In the given question information given about a plot 55 metre long and 30 metre wide at the rate of rupees 4.50 per square metre.

• We have to find the cost of levelling the total field.

 \underline {\underline\bold{Given : }} \\  \implies  \text{Long = 55 m} \\  \\  \implies  \text{Wide = 30 m} \\  \\  \implies  {Cost  \: of \: levelling =4.5  \: rupees m^{2} }  \\  \\ \underline {\underline\bold{To \: Find: }} \\  \implies  \text{Cost \: levelling \: the \: ground = ?}

• According to given question :

 \text{Using \: formula \: of \: } \bold{Area \: of \: rectangle : } \\  \implies Area \: of \: rectangle = L \times B \\  \\  \implies Area = (55 \times 30)m \\  \\  \implies Area = 1650 \:   {m}^{2}  \\  \\  \bold{Using \: unitary \: method : } \\  \implies Cost \: of \: levelling \: 1 { m}^{2}  \: field = 4.5 \: rupees \\  \\   \implies Cost \: of \: levelling \: 1650 \:  { m}^{2}  \: field = 4.5 \times 1650 \\  \\   \bold{\implies Cost  \: of \:levelling = 7425  \: rupees} \\  \\  \therefore   \text{Cost \: of \: levelling }\: 1650 {m}^{2}  \:  \text{field = 7425 \:rupees}


Anonymous: Well answer
BrainlyConqueror0901: : )
StarrySoul: Nice one! ◕ ‿ ◕
BrainlyConqueror0901: : )
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